Help: clarify that list(APPEND) on a non-existent list creates it

This is hinted-at in the introduction, which mentions creating
a new variable value in the current scope, but let's make it
explicit.

Fixes: #22910
This commit is contained in:
Adriaan de Groot
2021-12-21 15:34:48 +01:00
committed by Brad King
parent 6afe949658
commit e55f473ea9

View File

@@ -128,7 +128,9 @@ Modification
list(APPEND <list> [<element> ...])
Appends elements to the list.
Appends elements to the list. If no variable named ``<list>`` exists in the
current scope its value is treated as empty and the elements are appended to
that empty list.
.. _FILTER: