diff --git a/modules/space/rendering/renderableorbitalkepler.cpp b/modules/space/rendering/renderableorbitalkepler.cpp
index 06e3cebcb7..620cce37d8 100644
--- a/modules/space/rendering/renderableorbitalkepler.cpp
+++ b/modules/space/rendering/renderableorbitalkepler.cpp
@@ -60,7 +60,7 @@ namespace {
     };
 
     // Find the position of the current year in the vector; its position in
-// the vector gives the number of leap seconds
+    // the vector gives the number of leap seconds
     struct LeapSecond {
         int year;
         int dayOfYear;
@@ -246,9 +246,7 @@ double RenderableOrbitalKepler::epochFromSubstring(const std::string& epochStrin
 
     // The main overview of this function:
     // 1. Reconstruct the full year from the YY part
-    // 2. Calculate the number of seconds since the beginning of the year
-    // 2.a Get the number of full days since the beginning of the year
-    // 2.b If the year is a leap year, modify the number of days
+    // 2. Calculate the number of days since the beginning of the year
     // 3. Convert the number of days to a number of seconds
     // 4. Get the number of leap seconds since January 1st, 2000 and remove them
     // 5. Adjust for the fact the epoch starts on 1st Januaray at 12:00:00, not
@@ -267,18 +265,8 @@ double RenderableOrbitalKepler::epochFromSubstring(const std::string& epochStrin
     const int daysSince2000 = countDays(year);
 
     // 2.
-    // 2.a
     double daysInYear = std::atof(epochString.substr(2).c_str());
 
-    // 2.b
-    const bool isInLeapYear =
-        std::find(LeapYears.begin(), LeapYears.end(), year) != LeapYears.end();
-    if (isInLeapYear && daysInYear >= 60) {
-        // We are in a leap year, so we have an effective day more if we are
-        // beyond the end of february (= 31+29 days)
-        --daysInYear;
-    }
-
     // 3
     using namespace std::chrono;
     const int SecondsPerDay = static_cast<int>(seconds(hours(24)).count());
@@ -309,9 +297,7 @@ double RenderableOrbitalKepler::epochFromYMDdSubstring(const std::string& epochS
 
     // The main overview of this function:
     // 1. Read the year value
-    // 2. Calculate the number of seconds since the beginning of the year
-    // 2.a Get the number of full days since the beginning of the year
-    // 2.b If the year is a leap year, modify the number of days
+    // 2. Calculate the number of days since the beginning of the year
     // 3. Convert the number of days to a number of seconds
     // 4. Get the number of leap seconds since January 1st, 2000 and remove them
     // 5. Adjust for the fact the epoch starts on 1st January at 12:00:00, not
@@ -322,22 +308,12 @@ double RenderableOrbitalKepler::epochFromYMDdSubstring(const std::string& epochS
     const int daysSince2000 = countDays(year);
 
     // 2.
-    // 2.a
     int monthNum = std::atoi(epochString.substr(4, 2).c_str());
     int dayOfMonthNum = std::atoi(epochString.substr(6, 2).c_str());
     int wholeDaysInto = daysIntoGivenYear(monthNum, dayOfMonthNum);
     double fractionOfDay = std::atof(epochString.substr(9, 7).c_str());
     double daysInYear = static_cast<double>(wholeDaysInto) + fractionOfDay;
 
-    // 2.b
-    const bool isInLeapYear =
-        std::find(LeapYears.begin(), LeapYears.end(), year) != LeapYears.end();
-    if (isInLeapYear && daysInYear >= 60) {
-        // We are in a leap year, so we have an effective day more if we are
-        // beyond the end of february (= 31+29 days)
-        --daysInYear;
-    }
-
     // 3
     using namespace std::chrono;
     const int SecondsPerDay = static_cast<int>(seconds(hours(24)).count());
diff --git a/modules/space/translation/tletranslation.cpp b/modules/space/translation/tletranslation.cpp
index ec5fb75137..add42596de 100644
--- a/modules/space/translation/tletranslation.cpp
+++ b/modules/space/translation/tletranslation.cpp
@@ -145,9 +145,7 @@ namespace {
 
         // The main overview of this function:
         // 1. Reconstruct the full year from the YY part
-        // 2. Calculate the number of seconds since the beginning of the year
-        // 2.a Get the number of full days since the beginning of the year
-        // 2.b If the year is a leap year, modify the number of days
+        // 2. Calculate the number of days since the beginning of the year
         // 3. Convert the number of days to a number of seconds
         // 4. Get the number of leap seconds since January 1st, 2000 and remove them
         // 5. Adjust for the fact the epoch starts on 1st Januaray at 12:00:00, not
@@ -168,21 +166,8 @@ namespace {
         const int daysSince2000 = countDays(year);
 
         // 2.
-        // 2.a
         double daysInYear = std::atof(epochString.substr(2).c_str());
 
-        // 2.b
-        const bool isInLeapYear = std::find(
-            LeapYears.begin(),
-            LeapYears.end(),
-            year
-        ) != LeapYears.end();
-        if (isInLeapYear && daysInYear >= 60) {
-            // We are in a leap year, so we have an effective day more if we are
-            // beyond the end of february (= 31+29 days)
-            --daysInYear;
-        }
-
         // 3
         using namespace std::chrono;
         const int SecondsPerDay = static_cast<int>(seconds(hours(24)).count());