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30cc7d518f
This changes equal to compare by ref. Since computing the ref can be expensive we first check that the type refs are equal. Fixes #532
47 lines
1.1 KiB
Cheetah
47 lines
1.1 KiB
Cheetah
{{$typesPackage := .TypesPackage}}
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// {{.Name}}
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type {{.Name}} struct {
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target ref.Ref
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ref *ref.Ref
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}
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func New{{.Name}}(target ref.Ref) {{.Name}} {
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return {{.Name}}{target, &ref.Ref{}}
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}
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func (r {{.Name}}) TargetRef() ref.Ref {
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return r.target
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}
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func (r {{.Name}}) Ref() ref.Ref {
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return {{$typesPackage}}EnsureRef(r.ref, r)
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}
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func (r {{.Name}}) Equals(other {{$typesPackage}}Value) bool {
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return other != nil && __typeRefFor{{.Name}}.Equals(other.TypeRef()) && r.Ref() == other.Ref()
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}
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func (r {{.Name}}) Chunks() []ref.Ref {
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return r.TypeRef().Chunks()
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}
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func {{.Name}}FromVal(val {{$typesPackage}}Value) {{.Name}} {
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// TODO: Do we still need FromVal?
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if val, ok := val.({{.Name}}); ok {
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return val
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}
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return New{{.Name}}(val.({{$typesPackage}}Ref).TargetRef())
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}
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{{template "type_ref.tmpl" .}}
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func (r {{.Name}}) TargetValue(cs chunks.ChunkSource) {{userType .ElemType}} {
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return {{valueToUser (printf "%sReadValue(r.target, cs)" $typesPackage) .ElemType}}
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}
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func (r {{.Name}}) SetTargetValue(val {{userType .ElemType}}, cs chunks.ChunkSink) {{.Name}} {
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return New{{.Name}}({{$typesPackage}}WriteValue({{userToValue "val" .ElemType}}, cs))
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}
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