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Stabilize python default version lookup
For example, for sys.executable:
/usr/bin/python3 -> python3.7
...the default lookup may return either python3 or python3.7. Make the
order deterministic by iterating over tuple, not set, of candidates.
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@@ -43,14 +43,13 @@ def _find_by_py_launcher(version): # pragma: no cover (windows only)
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pass
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def _get_default_version(): # pragma: no cover (platform dependent)
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def _find_by_sys_executable():
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def _norm(path):
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_, exe = os.path.split(path.lower())
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exe, _, _ = exe.partition('.exe')
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if find_executable(exe) and exe not in {'python', 'pythonw'}:
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return exe
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# First attempt from `sys.executable` (or the realpath)
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# On linux, I see these common sys.executables:
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#
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# system `python`: /usr/bin/python -> python2.7
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@@ -59,10 +58,17 @@ def _get_default_version(): # pragma: no cover (platform dependent)
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# virtualenv v -ppython2: v/bin/python -> python2
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# virtualenv v -ppython2.7: v/bin/python -> python2.7
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# virtualenv v -ppypy: v/bin/python -> v/bin/pypy
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for path in {sys.executable, os.path.realpath(sys.executable)}:
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for path in (sys.executable, os.path.realpath(sys.executable)):
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exe = _norm(path)
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if exe:
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return exe
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return None
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def _get_default_version(): # pragma: no cover (platform dependent)
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# First attempt from `sys.executable` (or the realpath)
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exe = _find_by_sys_executable()
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# Next try the `pythonX.X` executable
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exe = 'python{}.{}'.format(*sys.version_info)
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